Solve (4*2-2^3/3)-(4*(-2)--2^3/3)

$$(4 \times 2- \frac{ { 2 }^{ 3 } }{ 3 } )-(4 \times (-2)- \frac{ { -2 }^{ 3 } }{ 3 } )$$

Evaluate

$$\frac{32}{3}\approx 10.666666667$$

Solution Steps

Multiply 4 and 2 to get 8.

$$8-\frac{2^{3}}{3}-\left(4\left(-2\right)-\frac{\left(-2\right)^{3}}{3}\right)$$

Calculate 2 to the power of 3 and get 8.

$$8-\frac{8}{3}-\left(4\left(-2\right)-\frac{\left(-2\right)^{3}}{3}\right)$$

Convert 8 to fraction \frac{24}{3}.

$$\frac{24}{3}-\frac{8}{3}-\left(4\left(-2\right)-\frac{\left(-2\right)^{3}}{3}\right)$$

Since \frac{24}{3} and \frac{8}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{24-8}{3}-\left(4\left(-2\right)-\frac{\left(-2\right)^{3}}{3}\right)$$

Subtract 8 from 24 to get 16.

$$\frac{16}{3}-\left(4\left(-2\right)-\frac{\left(-2\right)^{3}}{3}\right)$$

Multiply 4 and -2 to get -8.

$$\frac{16}{3}-\left(-8-\frac{\left(-2\right)^{3}}{3}\right)$$

Calculate -2 to the power of 3 and get -8.

$$\frac{16}{3}-\left(-8-\frac{-8}{3}\right)$$

Fraction \frac{-8}{3} can be rewritten as -\frac{8}{3} by extracting the negative sign.

$$\frac{16}{3}-\left(-8-\left(-\frac{8}{3}\right)\right)$$

The opposite of -\frac{8}{3} is \frac{8}{3}.

$$\frac{16}{3}-\left(-8+\frac{8}{3}\right)$$

Convert -8 to fraction -\frac{24}{3}.

$$\frac{16}{3}-\left(-\frac{24}{3}+\frac{8}{3}\right)$$

Since -\frac{24}{3} and \frac{8}{3} have the same denominator, add them by adding their numerators.

$$\frac{16}{3}-\frac{-24+8}{3}$$

Add -24 and 8 to get -16.

$$\frac{16}{3}-\left(-\frac{16}{3}\right)$$

The opposite of -\frac{16}{3} is \frac{16}{3}.

$$\frac{16}{3}+\frac{16}{3}$$

Since \frac{16}{3} and \frac{16}{3} have the same denominator, add them by adding their numerators.

$$\frac{16+16}{3}$$

Add 16 and 16 to get 32.

$$\frac{32}{3}$$

Factor

$$\frac{2 ^ {5}}{3} = 10\frac{2}{3} = 10.666666666666666$$