Solve (4*4-4^3/3)-(4*0-0^3/3)

$$(4 \cdot 4- \frac{ { 4 }^{ 3 } }{ 3 } )-(4 \times 0- \frac{ { 0 }^{ 3 } }{ 3 } )$$

Evaluate

$$-\frac{16}{3}\approx -5.333333333$$

Solution Steps

Multiply 4 and 4 to get 16.

$$16-\frac{4^{3}}{3}-\left(4\times 0-\frac{0^{3}}{3}\right)$$

Calculate 4 to the power of 3 and get 64.

$$16-\frac{64}{3}-\left(4\times 0-\frac{0^{3}}{3}\right)$$

Convert 16 to fraction \frac{48}{3}.

$$\frac{48}{3}-\frac{64}{3}-\left(4\times 0-\frac{0^{3}}{3}\right)$$

Since \frac{48}{3} and \frac{64}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{48-64}{3}-\left(4\times 0-\frac{0^{3}}{3}\right)$$

Subtract 64 from 48 to get -16.

$$-\frac{16}{3}-\left(4\times 0-\frac{0^{3}}{3}\right)$$

Multiply 4 and 0 to get 0.

$$-\frac{16}{3}-\left(0-\frac{0^{3}}{3}\right)$$

Calculate 0 to the power of 3 and get 0.

$$-\frac{16}{3}-\left(0-\frac{0}{3}\right)$$

Zero divided by any non-zero number gives zero.

$$-\frac{16}{3}-\left(0+0\right)$$

Add 0 and 0 to get 0.

$$-\frac{16}{3}-0$$

Subtract 0 from -\frac{16}{3} to get -\frac{16}{3}.

$$-\frac{16}{3}$$

Factor

$$-\frac{16}{3} = -5\frac{1}{3} = -5.333333333333333$$