Solve (3x-2)(2x-3)=(6x+5)(x+1)-1

$$(3x-2)(2x-3)=(6x+5)(x+1)-1$$

Solve for x

$$x=\frac{1}{12}\approx 0.083333333$$

Steps for Solving Linear Equation

Use the distributive property to multiply 3x-2 by 2x-3 and combine like terms.

$$6x^{2}-13x+6=\left(6x+5\right)\left(x+1\right)-1$$

Use the distributive property to multiply 6x+5 by x+1 and combine like terms.

$$6x^{2}-13x+6=6x^{2}+11x+5-1$$

Subtract 1 from 5 to get 4.

$$6x^{2}-13x+6=6x^{2}+11x+4$$

Subtract 6x^{2} from both sides.

$$6x^{2}-13x+6-6x^{2}=11x+4$$

Combine 6x^{2} and -6x^{2} to get 0.

$$-13x+6=11x+4$$

Subtract 11x from both sides.

$$-13x+6-11x=4$$

Combine -13x and -11x to get -24x.

$$-24x+6=4$$

Subtract 6 from both sides.

$$-24x=4-6$$

Subtract 6 from 4 to get -2.

$$-24x=-2$$

Divide both sides by -24.

$$x=\frac{-2}{-24}$$

Reduce the fraction \frac{-2}{-24} to lowest terms by extracting and canceling out -2.

$$x=\frac{1}{12}$$