Solve (35.5+36+37+38+39+40+41+42+43)div9

$$(35.5+36+37+38+39+40+41+42+43) \div 9$$

Evaluate

$$\frac{703}{18}\approx 39.055555556$$

Solution Steps

Add 35.5 and 36 to get 71.5.

$$\frac{71.5+37+38+39+40+41+42+43}{9}$$

Add 71.5 and 37 to get 108.5.

$$\frac{108.5+38+39+40+41+42+43}{9}$$

Add 108.5 and 38 to get 146.5.

$$\frac{146.5+39+40+41+42+43}{9}$$

Add 146.5 and 39 to get 185.5.

$$\frac{185.5+40+41+42+43}{9}$$

Add 185.5 and 40 to get 225.5.

$$\frac{225.5+41+42+43}{9}$$

Add 225.5 and 41 to get 266.5.

$$\frac{266.5+42+43}{9}$$

Add 266.5 and 42 to get 308.5.

$$\frac{308.5+43}{9}$$

Add 308.5 and 43 to get 351.5.

$$\frac{351.5}{9}$$

Expand \frac{351.5}{9} by multiplying both numerator and the denominator by 10.

$$\frac{3515}{90}$$

Reduce the fraction \frac{3515}{90} to lowest terms by extracting and canceling out 5.

$$\frac{703}{18}$$

Factor

$$\frac{19 \cdot 37}{2 \cdot 3 ^ {2}} = 39\frac{1}{18} = 39.05555555555556$$