Solve (3-6)(-12+5*3)-(4-5)(12-8)div4+10

$$(3-6)(-12+5 \times 3)-(4-5)(12-8) \div 4+10$$

Evaluate

$$2$$

Solution Steps

Subtract 6 from 3 to get -3.

$$-3\left(-12+5\times 3\right)-\frac{\left(4-5\right)\left(12-8\right)}{4}+10$$

Multiply 5 and 3 to get 15.

$$-3\left(-12+15\right)-\frac{\left(4-5\right)\left(12-8\right)}{4}+10$$

Add -12 and 15 to get 3.

$$-3\times 3-\frac{\left(4-5\right)\left(12-8\right)}{4}+10$$

Multiply -3 and 3 to get -9.

$$-9-\frac{\left(4-5\right)\left(12-8\right)}{4}+10$$

Subtract 5 from 4 to get -1.

$$-9-\frac{-\left(12-8\right)}{4}+10$$

Subtract 8 from 12 to get 4.

$$-9-\frac{-4}{4}+10$$

Divide -4 by 4 to get -1.

$$-9-\left(-1\right)+10$$

The opposite of -1 is 1.

$$-9+1+10$$

Add -9 and 1 to get -8.

$$-8+10$$

Add -8 and 10 to get 2.

$$2$$

Factor

$$2$$