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Differentiate w.r.t. x
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3^{2}-\left(\sqrt{5+x}\right)^{2}
Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
9-\left(\sqrt{5+x}\right)^{2}
Calculate 3 to the power of 2 and get 9.
9-\left(5+x\right)
Calculate \sqrt{5+x} to the power of 2 and get 5+x.
9-5-x
To find the opposite of 5+x, find the opposite of each term.
4-x
Subtract 5 from 9 to get 4.
\frac{\mathrm{d}}{\mathrm{d}x}(3^{2}-\left(\sqrt{5+x}\right)^{2})
Consider \left(3-\sqrt{5+x}\right)\left(3+\sqrt{5+x}\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{\mathrm{d}}{\mathrm{d}x}(9-\left(\sqrt{5+x}\right)^{2})
Calculate 3 to the power of 2 and get 9.
\frac{\mathrm{d}}{\mathrm{d}x}(9-\left(5+x\right))
Calculate \sqrt{5+x} to the power of 2 and get 5+x.
\frac{\mathrm{d}}{\mathrm{d}x}(9-5-x)
To find the opposite of 5+x, find the opposite of each term.
\frac{\mathrm{d}}{\mathrm{d}x}(4-x)
Subtract 5 from 9 to get 4.
-x^{1-1}
The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.
-x^{0}
Subtract 1 from 1.
-1
For any term t except 0, t^{0}=1.