Solve (3-4x/3)div5x1=4

$$(3- \frac{ 4x }{ 3 } ) \div 5x1=4$$

Solve for x

$$x=\frac{9}{4}-\frac{15}{x_{1}}$$

$$x_{1}\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 5.

$$\left(3-\frac{4x}{3}\right)x_{1}=20$$

Use the distributive property to multiply 3-\frac{4x}{3} by x_{1}.

$$3x_{1}+\left(-\frac{4x}{3}\right)x_{1}=20$$

Express \left(-\frac{4x}{3}\right)x_{1} as a single fraction.

$$3x_{1}+\frac{-4xx_{1}}{3}=20$$

Subtract 3x_{1} from both sides.

$$\frac{-4xx_{1}}{3}=20-3x_{1}$$

Multiply both sides of the equation by 3.

$$-4xx_{1}=60-9x_{1}$$

The equation is in standard form.

$$\left(-4x_{1}\right)x=60-9x_{1}$$

Divide both sides by -4x_{1}.

$$\frac{\left(-4x_{1}\right)x}{-4x_{1}}=\frac{60-9x_{1}}{-4x_{1}}$$

Dividing by -4x_{1} undoes the multiplication by -4x_{1}.

$$x=\frac{60-9x_{1}}{-4x_{1}}$$

Divide 60-9x_{1} by -4x_{1}.

$$x=\frac{9}{4}-\frac{15}{x_{1}}$$

Solve for x_1

$$x_{1}=\frac{60}{9-4x}$$

$$x\neq \frac{9}{4}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 5.

$$\left(3-\frac{4x}{3}\right)x_{1}=20$$

Use the distributive property to multiply 3-\frac{4x}{3} by x_{1}.

$$3x_{1}+\left(-\frac{4x}{3}\right)x_{1}=20$$

Express \left(-\frac{4x}{3}\right)x_{1} as a single fraction.

$$3x_{1}+\frac{-4xx_{1}}{3}=20$$

Multiply both sides of the equation by 3.

$$9x_{1}-4xx_{1}=60$$

Combine all terms containing x_{1}.

$$\left(9-4x\right)x_{1}=60$$

Divide both sides by 9-4x.

$$\frac{\left(9-4x\right)x_{1}}{9-4x}=\frac{60}{9-4x}$$

Dividing by 9-4x undoes the multiplication by 9-4x.

$$x_{1}=\frac{60}{9-4x}$$