Solve (3+2/5)div(1/6-5)

$$(3+ \frac{ 2 }{ 5 } ) \div ( \frac{ 1 }{ 6 } -5)$$

Evaluate

$$-\frac{102}{145}\approx -0.703448276$$

Solution Steps

Convert 3 to fraction \frac{15}{5}.

$$\frac{\frac{15}{5}+\frac{2}{5}}{\frac{1}{6}-5}$$

Since \frac{15}{5} and \frac{2}{5} have the same denominator, add them by adding their numerators.

$$\frac{\frac{15+2}{5}}{\frac{1}{6}-5}$$

Add 15 and 2 to get 17.

$$\frac{\frac{17}{5}}{\frac{1}{6}-5}$$

Convert 5 to fraction \frac{30}{6}.

$$\frac{\frac{17}{5}}{\frac{1}{6}-\frac{30}{6}}$$

Since \frac{1}{6} and \frac{30}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{17}{5}}{\frac{1-30}{6}}$$

Subtract 30 from 1 to get -29.

$$\frac{\frac{17}{5}}{-\frac{29}{6}}$$

Divide \frac{17}{5} by -\frac{29}{6} by multiplying \frac{17}{5} by the reciprocal of -\frac{29}{6}.

$$\frac{17}{5}\left(-\frac{6}{29}\right)$$

Multiply \frac{17}{5} times -\frac{6}{29} by multiplying numerator times numerator and denominator times denominator.

$$\frac{17\left(-6\right)}{5\times 29}$$

Do the multiplications in the fraction \frac{17\left(-6\right)}{5\times 29}.

$$\frac{-102}{145}$$

Fraction \frac{-102}{145} can be rewritten as -\frac{102}{145} by extracting the negative sign.

$$-\frac{102}{145}$$

Factor

$$-\frac{102}{145} = -0.7034482758620689$$