Solve (3+1/4)-(2+1/6)

$$(3+ \frac{ 1 }{ 4 } )-(2+ \frac{ 1 }{ 6 } )$$

Evaluate

$$\frac{13}{12}\approx 1.083333333$$

Solution Steps

Convert 3 to fraction \frac{12}{4}.

$$\frac{12}{4}+\frac{1}{4}-\left(2+\frac{1}{6}\right)$$

Since \frac{12}{4} and \frac{1}{4} have the same denominator, add them by adding their numerators.

$$\frac{12+1}{4}-\left(2+\frac{1}{6}\right)$$

Add 12 and 1 to get 13.

$$\frac{13}{4}-\left(2+\frac{1}{6}\right)$$

Convert 2 to fraction \frac{12}{6}.

$$\frac{13}{4}-\left(\frac{12}{6}+\frac{1}{6}\right)$$

Since \frac{12}{6} and \frac{1}{6} have the same denominator, add them by adding their numerators.

$$\frac{13}{4}-\frac{12+1}{6}$$

Add 12 and 1 to get 13.

$$\frac{13}{4}-\frac{13}{6}$$

Least common multiple of 4 and 6 is 12. Convert \frac{13}{4} and \frac{13}{6} to fractions with denominator 12.

$$\frac{39}{12}-\frac{26}{12}$$

Since \frac{39}{12} and \frac{26}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{39-26}{12}$$

Subtract 26 from 39 to get 13.

$$\frac{13}{12}$$

Factor

$$\frac{13}{2 ^ {2} \cdot 3} = 1\frac{1}{12} = 1.0833333333333333$$