Solve (3*2^-2+2*2^-1+7*2)

$$(3 \times { 2 }^{ -2 } +2 \times { 2 }^{ -1 } +7 \times 2)$$

Evaluate

$$\frac{63}{4}=15.75$$

Solution Steps

Multiply 2 and 2^{-1} to get 1.

$$3\times 2^{-2}+1+7\times 2$$

Calculate 2 to the power of -2 and get \frac{1}{4}.

$$3\times \frac{1}{4}+1+7\times 2$$

Multiply 3 and \frac{1}{4} to get \frac{3}{4}.

$$\frac{3}{4}+1+7\times 2$$

Add \frac{3}{4} and 1 to get \frac{7}{4}.

$$\frac{7}{4}+7\times 2$$

Multiply 7 and 2 to get 14.

$$\frac{7}{4}+14$$

Add \frac{7}{4} and 14 to get \frac{63}{4}.

$$\frac{63}{4}$$

Factor

$$\frac{3 ^ {2} \cdot 7}{2 ^ {2}} = 15\frac{3}{4} = 15.75$$