Solve (37/8-21/4)div(31/4*1/2)

$$(3 \frac{ 7 }{ 8 } -2 \frac{ 1 }{ 4 } ) \div (3 \frac{ 1 }{ 4 } \times \frac{ 1 }{ 2 } )$$

Evaluate

$$1$$

Solution Steps

Multiply 3 and 8 to get 24.

$$\frac{\frac{24+7}{8}-\frac{2\times 4+1}{4}}{\frac{3\times 4+1}{4}\times \frac{1}{2}}$$

Add 24 and 7 to get 31.

$$\frac{\frac{31}{8}-\frac{2\times 4+1}{4}}{\frac{3\times 4+1}{4}\times \frac{1}{2}}$$

Multiply 2 and 4 to get 8.

$$\frac{\frac{31}{8}-\frac{8+1}{4}}{\frac{3\times 4+1}{4}\times \frac{1}{2}}$$

Add 8 and 1 to get 9.

$$\frac{\frac{31}{8}-\frac{9}{4}}{\frac{3\times 4+1}{4}\times \frac{1}{2}}$$

Least common multiple of 8 and 4 is 8. Convert \frac{31}{8} and \frac{9}{4} to fractions with denominator 8.

$$\frac{\frac{31}{8}-\frac{18}{8}}{\frac{3\times 4+1}{4}\times \frac{1}{2}}$$

Since \frac{31}{8} and \frac{18}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{31-18}{8}}{\frac{3\times 4+1}{4}\times \frac{1}{2}}$$

Subtract 18 from 31 to get 13.

$$\frac{\frac{13}{8}}{\frac{3\times 4+1}{4}\times \frac{1}{2}}$$

Multiply 3 and 4 to get 12.

$$\frac{\frac{13}{8}}{\frac{12+1}{4}\times \frac{1}{2}}$$

Add 12 and 1 to get 13.

$$\frac{\frac{13}{8}}{\frac{13}{4}\times \frac{1}{2}}$$

Multiply \frac{13}{4} times \frac{1}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\frac{13}{8}}{\frac{13\times 1}{4\times 2}}$$

Do the multiplications in the fraction \frac{13\times 1}{4\times 2}.

$$\frac{\frac{13}{8}}{\frac{13}{8}}$$

Divide \frac{13}{8} by \frac{13}{8} to get 1.

$$1$$

Factor

$$1$$