Solve (2x-8)+(3x)+(xdiv2)+(x-7)+(4x-13)=56

$$(2x-8)+(3x)+(x \div 2)+(x-7)+(4x-13)=56$$

Solve for x

$$x=8$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2.

$$4x-16+6x+x+2x-14+8x-26=112$$

Combine 4x and 6x to get 10x.

$$10x-16+x+2x-14+8x-26=112$$

Combine 10x and x to get 11x.

$$11x-16+2x-14+8x-26=112$$

Combine 11x and 2x to get 13x.

$$13x-16-14+8x-26=112$$

Subtract 14 from -16 to get -30.

$$13x-30+8x-26=112$$

Combine 13x and 8x to get 21x.

$$21x-30-26=112$$

Subtract 26 from -30 to get -56.

$$21x-56=112$$

Add 56 to both sides.

$$21x=112+56$$

Add 112 and 56 to get 168.

$$21x=168$$

Divide both sides by 21.

$$x=\frac{168}{21}$$

Divide 168 by 21 to get 8.

$$x=8$$