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\left(2x\right)^{2}-1-\left(4x-3\right)=4x\left(x-2\right)
Consider \left(2x-1\right)\left(2x+1\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Square 1.
2^{2}x^{2}-1-\left(4x-3\right)=4x\left(x-2\right)
Expand \left(2x\right)^{2}.
4x^{2}-1-\left(4x-3\right)=4x\left(x-2\right)
Calculate 2 to the power of 2 and get 4.
4x^{2}-1-4x+3=4x\left(x-2\right)
To find the opposite of 4x-3, find the opposite of each term.
4x^{2}+2-4x=4x\left(x-2\right)
Add -1 and 3 to get 2.
4x^{2}+2-4x=4x^{2}-8x
Use the distributive property to multiply 4x by x-2.
4x^{2}+2-4x-4x^{2}=-8x
Subtract 4x^{2} from both sides.
2-4x=-8x
Combine 4x^{2} and -4x^{2} to get 0.
2-4x+8x=0
Add 8x to both sides.
2+4x=0
Combine -4x and 8x to get 4x.
4x=-2
Subtract 2 from both sides. Anything subtracted from zero gives its negation.
x=\frac{-2}{4}
Divide both sides by 4.
x=-\frac{1}{2}
Reduce the fraction \frac{-2}{4} to lowest terms by extracting and canceling out 2.