Solve (2x*9)-23+5x*3^2

$$(2x \times 9)-23+5x \times { 3 }^{ 2 }$$

Evaluate

$$63x-23$$

Solution Steps

Multiply 2 and 9 to get 18.

$$18x-23+5x\times 3^{2}$$

Calculate 3 to the power of 2 and get 9.

$$18x-23+5x\times 9$$

Multiply 5 and 9 to get 45.

$$18x-23+45x$$

Combine 18x and 45x to get 63x.

$$63x-23$$

Differentiate w.r.t. x

$$63$$

Steps Using Derivative Rule for Sum

Multiply 2 and 9 to get 18.

$$\frac{\mathrm{d}}{\mathrm{d}x}(18x-23+5x\times 3^{2})$$

Calculate 3 to the power of 2 and get 9.

$$\frac{\mathrm{d}}{\mathrm{d}x}(18x-23+5x\times 9)$$

Multiply 5 and 9 to get 45.

$$\frac{\mathrm{d}}{\mathrm{d}x}(18x-23+45x)$$

Combine 18x and 45x to get 63x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(63x-23)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$63x^{1-1}$$

Subtract 1 from 1.

$$63x^{0}$$

For any term t except 0, t^{0}=1.

$$63\times 1$$

For any term t, t\times 1=t and 1t=t.

$$63$$