Solve (24-7*8)div8*(-7)-56div(1-8)+48div(-10-2

$$(24-7 \times 8) \div 8 \times (-7)-56 \div (1-8)+48 \div (-10-2$$

Evaluate

$$32$$

Solution Steps

Multiply 7 and 8 to get 56.

$$\frac{24-56}{8}\left(-7\right)-\frac{56}{1-8}+\frac{48}{-10-2}$$

Subtract 56 from 24 to get -32.

$$\frac{-32}{8}\left(-7\right)-\frac{56}{1-8}+\frac{48}{-10-2}$$

Divide -32 by 8 to get -4.

$$-4\left(-7\right)-\frac{56}{1-8}+\frac{48}{-10-2}$$

Multiply -4 and -7 to get 28.

$$28-\frac{56}{1-8}+\frac{48}{-10-2}$$

Subtract 8 from 1 to get -7.

$$28-\frac{56}{-7}+\frac{48}{-10-2}$$

Divide 56 by -7 to get -8.

$$28-\left(-8\right)+\frac{48}{-10-2}$$

The opposite of -8 is 8.

$$28+8+\frac{48}{-10-2}$$

Add 28 and 8 to get 36.

$$36+\frac{48}{-10-2}$$

Subtract 2 from -10 to get -12.

$$36+\frac{48}{-12}$$

Divide 48 by -12 to get -4.

$$36-4$$

Subtract 4 from 36 to get 32.

$$32$$

Factor

$$2^{5}$$