Solve (24+(3-8-4)div(4-9)

$$(24+(3-8-4) \div (4-9)$$

Evaluate

$$\frac{129}{5}=25.8$$

Solution Steps

Subtract 8 from 3 to get -5.

$$24+\frac{-5-4}{4-9}$$

Subtract 4 from -5 to get -9.

$$24+\frac{-9}{4-9}$$

Subtract 9 from 4 to get -5.

$$24+\frac{-9}{-5}$$

Fraction \frac{-9}{-5} can be simplified to \frac{9}{5} by removing the negative sign from both the numerator and the denominator.

$$24+\frac{9}{5}$$

Convert 24 to fraction \frac{120}{5}.

$$\frac{120}{5}+\frac{9}{5}$$

Since \frac{120}{5} and \frac{9}{5} have the same denominator, add them by adding their numerators.

$$\frac{120+9}{5}$$

Add 120 and 9 to get 129.

$$\frac{129}{5}$$

Factor

$$\frac{3 \cdot 43}{5} = 25\frac{4}{5} = 25.8$$