Solve (2003)+(-1/2003)

$$(2003)+(- \frac{ 1 }{ 2003 } )$$

Evaluate

$$\frac{4012008}{2003}\approx 2002.999500749$$

Solution Steps

Convert 2003 to fraction \frac{4012009}{2003}.

$$\frac{4012009}{2003}-\frac{1}{2003}$$

Since \frac{4012009}{2003} and \frac{1}{2003} have the same denominator, subtract them by subtracting their numerators.

$$\frac{4012009-1}{2003}$$

Subtract 1 from 4012009 to get 4012008.

$$\frac{4012008}{2003}$$

Factor

$$\frac{2 ^ {3} \cdot 3 \cdot 7 \cdot 11 \cdot 13 \cdot 167}{2003} = 2002\frac{2002}{2003} = 2002.9995007488767$$