Solve (200div22+200div605)

$$(200 \div 22+200 \div 605)$$

Evaluate

$$\frac{1140}{121}\approx 9.421487603$$

Solution Steps

Reduce the fraction \frac{200}{22} to lowest terms by extracting and canceling out 2.

$$\frac{100}{11}+\frac{200}{605}$$

Reduce the fraction \frac{200}{605} to lowest terms by extracting and canceling out 5.

$$\frac{100}{11}+\frac{40}{121}$$

Least common multiple of 11 and 121 is 121. Convert \frac{100}{11} and \frac{40}{121} to fractions with denominator 121.

$$\frac{1100}{121}+\frac{40}{121}$$

Since \frac{1100}{121} and \frac{40}{121} have the same denominator, add them by adding their numerators.

$$\frac{1100+40}{121}$$

Add 1100 and 40 to get 1140.

$$\frac{1140}{121}$$

Factor

$$\frac{2 ^ {2} \cdot 3 \cdot 5 \cdot 19}{11 ^ {2}} = 9\frac{51}{121} = 9.421487603305785$$