Solve (2*4^2+5)-(2*-2^2+5)

$$(2 \times { 4 }^{ 2 } +5)-(2 \times - { 2 }^{ 2 } +5)$$

Evaluate

$$40$$

Solution Steps

Calculate 4 to the power of 2 and get 16.

$$2\times 16+5-\left(2\left(-2^{2}\right)+5\right)$$

Multiply 2 and 16 to get 32.

$$32+5-\left(2\left(-2^{2}\right)+5\right)$$

Add 32 and 5 to get 37.

$$37-\left(2\left(-2^{2}\right)+5\right)$$

Calculate 2 to the power of 2 and get 4.

$$37-\left(2\left(-4\right)+5\right)$$

Multiply 2 and -4 to get -8.

$$37-\left(-8+5\right)$$

Add -8 and 5 to get -3.

$$37-\left(-3\right)$$

The opposite of -3 is 3.

$$37+3$$

Add 37 and 3 to get 40.

$$40$$

Factor

$$2^{3}\times 5$$