Solve (17-4)+3-(12-5*2)+(5+16/4)-5+(10-2^3)

$$(17-4)+3-(12-5 \times 2)+(5+ \frac{ 16 }{ 4 } )-5+(10- { 2 }^{ 3 } )$$

Evaluate

$$20$$

Solution Steps

Subtract 4 from 17 to get 13.

$$13+3-\left(12-5\times 2\right)+5+\frac{16}{4}-5+10-2^{3}$$

Add 13 and 3 to get 16.

$$16-\left(12-5\times 2\right)+5+\frac{16}{4}-5+10-2^{3}$$

Multiply 5 and 2 to get 10.

$$16-\left(12-10\right)+5+\frac{16}{4}-5+10-2^{3}$$

Subtract 10 from 12 to get 2.

$$16-2+5+\frac{16}{4}-5+10-2^{3}$$

Subtract 2 from 16 to get 14.

$$14+5+\frac{16}{4}-5+10-2^{3}$$

Add 14 and 5 to get 19.

$$19+\frac{16}{4}-5+10-2^{3}$$

Divide 16 by 4 to get 4.

$$19+4-5+10-2^{3}$$

Add 19 and 4 to get 23.

$$23-5+10-2^{3}$$

Subtract 5 from 23 to get 18.

$$18+10-2^{3}$$

Calculate 2 to the power of 3 and get 8.

$$18+10-8$$

Subtract 8 from 10 to get 2.

$$18+2$$

Add 18 and 2 to get 20.

$$20$$

Factor

$$2^{2}\times 5$$