Solve (11+0.45/8)div30%

$$(11+0.4 \frac{ 5 }{ 8 } ) \div 30 \%$$

Evaluate

$$\frac{481}{12}\approx 40.083333333$$

Solution Steps

Multiply 0.4 and 8 to get 3.2.

$$\frac{11+\frac{3.2+5}{8}}{\frac{30}{100}}$$

Add 3.2 and 5 to get 8.2.

$$\frac{11+\frac{8.2}{8}}{\frac{30}{100}}$$

Expand \frac{8.2}{8} by multiplying both numerator and the denominator by 10.

$$\frac{11+\frac{82}{80}}{\frac{30}{100}}$$

Reduce the fraction \frac{82}{80} to lowest terms by extracting and canceling out 2.

$$\frac{11+\frac{41}{40}}{\frac{30}{100}}$$

Convert 11 to fraction \frac{440}{40}.

$$\frac{\frac{440}{40}+\frac{41}{40}}{\frac{30}{100}}$$

Since \frac{440}{40} and \frac{41}{40} have the same denominator, add them by adding their numerators.

$$\frac{\frac{440+41}{40}}{\frac{30}{100}}$$

Add 440 and 41 to get 481.

$$\frac{\frac{481}{40}}{\frac{30}{100}}$$

Reduce the fraction \frac{30}{100} to lowest terms by extracting and canceling out 10.

$$\frac{\frac{481}{40}}{\frac{3}{10}}$$

Divide \frac{481}{40} by \frac{3}{10} by multiplying \frac{481}{40} by the reciprocal of \frac{3}{10}.

$$\frac{481}{40}\times \frac{10}{3}$$

Multiply \frac{481}{40} times \frac{10}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{481\times 10}{40\times 3}$$

Do the multiplications in the fraction \frac{481\times 10}{40\times 3}.

$$\frac{4810}{120}$$

Reduce the fraction \frac{4810}{120} to lowest terms by extracting and canceling out 10.

$$\frac{481}{12}$$

Factor

$$\frac{13 \cdot 37}{3 \cdot 2 ^ {2}} = 40\frac{1}{12} = 40.083333333333336$$