Solve (103+998)div(998-103/5+1)*05

$$(103+998) \div ( \frac{ 998-103 }{ 5 } +1) \times 05$$

Evaluate

$$0$$

Solution Steps

Add 103 and 998 to get 1101.

$$\frac{1101}{\frac{998-103}{5}+1}\times 0\times 5$$

Subtract 103 from 998 to get 895.

$$\frac{1101}{\frac{895}{5}+1}\times 0\times 5$$

Divide 895 by 5 to get 179.

$$\frac{1101}{179+1}\times 0\times 5$$

Add 179 and 1 to get 180.

$$\frac{1101}{180}\times 0\times 5$$

Reduce the fraction \frac{1101}{180} to lowest terms by extracting and canceling out 3.

$$\frac{367}{60}\times 0\times 5$$

Multiply \frac{367}{60} and 0 to get 0.

$$0\times 5$$

Multiply 0 and 5 to get 0.

$$0$$

Factor

$$0$$