Solve (103+998)div(998-103/5+1)*0.5

$$(103+998) \div ( \frac{ 998-103 }{ 5 } +1) \times 0.5$$

Evaluate

$$\frac{367}{120}\approx 3.058333333$$

Solution Steps

Add 103 and 998 to get 1101.

$$\frac{1101}{\frac{998-103}{5}+1}\times 0.5$$

Subtract 103 from 998 to get 895.

$$\frac{1101}{\frac{895}{5}+1}\times 0.5$$

Divide 895 by 5 to get 179.

$$\frac{1101}{179+1}\times 0.5$$

Add 179 and 1 to get 180.

$$\frac{1101}{180}\times 0.5$$

Reduce the fraction \frac{1101}{180} to lowest terms by extracting and canceling out 3.

$$\frac{367}{60}\times 0.5$$

Convert decimal number 0.5 to fraction \frac{5}{10}. Reduce the fraction \frac{5}{10} to lowest terms by extracting and canceling out 5.

$$\frac{367}{60}\times \frac{1}{2}$$

Multiply \frac{367}{60} times \frac{1}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{367\times 1}{60\times 2}$$

Do the multiplications in the fraction \frac{367\times 1}{60\times 2}.

$$\frac{367}{120}$$

Factor

$$\frac{367}{3 \cdot 5 \cdot 2 ^ {3}} = 3\frac{7}{120} = 3.058333333333333$$