Solve for x
x=25
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\frac{100}{3}-\frac{1}{3}x=x
Divide each term of 100-x by 3 to get \frac{100}{3}-\frac{1}{3}x.
\frac{100}{3}-\frac{1}{3}x-x=0
Subtract x from both sides.
\frac{100}{3}-\frac{4}{3}x=0
Combine -\frac{1}{3}x and -x to get -\frac{4}{3}x.
-\frac{4}{3}x=-\frac{100}{3}
Subtract \frac{100}{3} from both sides. Anything subtracted from zero gives its negation.
x=-\frac{100}{3}\left(-\frac{3}{4}\right)
Multiply both sides by -\frac{3}{4}, the reciprocal of -\frac{4}{3}.
x=\frac{-100\left(-3\right)}{3\times 4}
Multiply -\frac{100}{3} times -\frac{3}{4} by multiplying numerator times numerator and denominator times denominator.
x=\frac{300}{12}
Do the multiplications in the fraction \frac{-100\left(-3\right)}{3\times 4}.
x=25
Divide 300 by 12 to get 25.
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