Solve (1-7+2)(7+2)=(-1+7-2)(-7-2)

$$(1-7+2)(7+2)=(-1+7-2)(-7-2)$$

Verify

Solution Steps

Subtract 7 from 1 to get -6.

$$\left(-6+2\right)\left(7+2\right)=\left(-1+7-2\right)\left(-7-2\right)$$

Add -6 and 2 to get -4.

$$-4\left(7+2\right)=\left(-1+7-2\right)\left(-7-2\right)$$

Add 7 and 2 to get 9.

$$-4\times 9=\left(-1+7-2\right)\left(-7-2\right)$$

Multiply -4 and 9 to get -36.

$$-36=\left(-1+7-2\right)\left(-7-2\right)$$

Add -1 and 7 to get 6.

$$-36=\left(6-2\right)\left(-7-2\right)$$

Subtract 2 from 6 to get 4.

$$-36=4\left(-7-2\right)$$

Subtract 2 from -7 to get -9.

$$-36=4\left(-9\right)$$

Multiply 4 and -9 to get -36.

$$-36=-36$$

Compare -36 and -36.

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