Solve (1-3x)<2x-3/3

$$(1-3x) < \frac{ 2x-3 }{ 3 }$$

Solve for x

$$x>\frac{6}{11}$$

Solution Steps

Multiply both sides of the equation by 3. Since 3 is positive, the inequality direction remains the same.

$$3-9x<2x-3$$

Subtract 2x from both sides.

$$3-9x-2x<-3$$

Combine -9x and -2x to get -11x.

$$3-11x<-3$$

Subtract 3 from both sides.

$$-11x<-3-3$$

Subtract 3 from -3 to get -6.

$$-11x<-6$$

Divide both sides by -11. Since -11 is negative, the inequality direction is changed.

$$x>\frac{-6}{-11}$$

Fraction \frac{-6}{-11} can be simplified to \frac{6}{11} by removing the negative sign from both the numerator and the denominator.

$$x>\frac{6}{11}$$