Solve (1-3/1)div2/3+1/18=

$$(1- \frac{ 3 }{ 1 } ) \div \frac{ 2 }{ 3 } + \frac{ 1 }{ 18 } =$$

Evaluate

$$-\frac{53}{18}\approx -2.944444444$$

Solution Steps

Anything divided by one gives itself.

$$\frac{1-3}{\frac{2}{3}}+\frac{1}{18}$$

Subtract 3 from 1 to get -2.

$$\frac{-2}{\frac{2}{3}}+\frac{1}{18}$$

Divide -2 by \frac{2}{3} by multiplying -2 by the reciprocal of \frac{2}{3}.

$$-2\times \frac{3}{2}+\frac{1}{18}$$

Multiply -2 times \frac{3}{2}.

$$-3+\frac{1}{18}$$

Convert -3 to fraction -\frac{54}{18}.

$$-\frac{54}{18}+\frac{1}{18}$$

Since -\frac{54}{18} and \frac{1}{18} have the same denominator, add them by adding their numerators.

$$\frac{-54+1}{18}$$

Add -54 and 1 to get -53.

$$-\frac{53}{18}$$

Factor

$$-\frac{53}{18} = -2\frac{17}{18} = -2.9444444444444446$$