Solve (1+x)128=608

$$(1+x)128=608$$

Solve for x

$$x = \frac{15}{4} = 3\frac{3}{4} = 3.75$$

Steps for Solving Linear Equation

Divide both sides by 128.

$$1+x=\frac{608}{128}$$

Reduce the fraction \frac{608}{128} to lowest terms by extracting and canceling out 32.

$$1+x=\frac{19}{4}$$

Subtract 1 from both sides.

$$x=\frac{19}{4}-1$$

Convert 1 to fraction \frac{4}{4}.

$$x=\frac{19}{4}-\frac{4}{4}$$

Since \frac{19}{4} and \frac{4}{4} have the same denominator, subtract them by subtracting their numerators.

$$x=\frac{19-4}{4}$$

Subtract 4 from 19 to get 15.

$$x=\frac{15}{4}$$