Solve (1+40%)x*80%=x+15

$$(1+40 \% )x \times 80 \% =x+15$$

Solve for x

$$x=125$$

Steps for Solving Linear Equation

Reduce the fraction \frac{40}{100} to lowest terms by extracting and canceling out 20.

$$\left(1+\frac{2}{5}\right)x\times \frac{80}{100}=x+15$$

Convert 1 to fraction \frac{5}{5}.

$$\left(\frac{5}{5}+\frac{2}{5}\right)x\times \frac{80}{100}=x+15$$

Since \frac{5}{5} and \frac{2}{5} have the same denominator, add them by adding their numerators.

$$\frac{5+2}{5}x\times \frac{80}{100}=x+15$$

Add 5 and 2 to get 7.

$$\frac{7}{5}x\times \frac{80}{100}=x+15$$

Reduce the fraction \frac{80}{100} to lowest terms by extracting and canceling out 20.

$$\frac{7}{5}x\times \frac{4}{5}=x+15$$

Multiply \frac{7}{5} times \frac{4}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7\times 4}{5\times 5}x=x+15$$

Do the multiplications in the fraction \frac{7\times 4}{5\times 5}.

$$\frac{28}{25}x=x+15$$

Subtract x from both sides.

$$\frac{28}{25}x-x=15$$

Combine \frac{28}{25}x and -x to get \frac{3}{25}x.

$$\frac{3}{25}x=15$$

Multiply both sides by \frac{25}{3}, the reciprocal of \frac{3}{25}.

$$x=15\times \frac{25}{3}$$

Express 15\times \frac{25}{3} as a single fraction.

$$x=\frac{15\times 25}{3}$$

Multiply 15 and 25 to get 375.

$$x=\frac{375}{3}$$

Divide 375 by 3 to get 125.

$$x=125$$