Solve (1+3+9div2+27div6+81div24+271div120)

$$(1+3+9 \div 2+27 \div 6+81 \div 24+271 \div 120)$$

Evaluate

$$\frac{559}{30}\approx 18.633333333$$

Solution Steps

Add 1 and 3 to get 4.

$$4+\frac{9}{2}+\frac{27}{6}+\frac{81}{24}+\frac{271}{120}$$

Convert 4 to fraction \frac{8}{2}.

$$\frac{8}{2}+\frac{9}{2}+\frac{27}{6}+\frac{81}{24}+\frac{271}{120}$$

Since \frac{8}{2} and \frac{9}{2} have the same denominator, add them by adding their numerators.

$$\frac{8+9}{2}+\frac{27}{6}+\frac{81}{24}+\frac{271}{120}$$

Add 8 and 9 to get 17.

$$\frac{17}{2}+\frac{27}{6}+\frac{81}{24}+\frac{271}{120}$$

Reduce the fraction \frac{27}{6} to lowest terms by extracting and canceling out 3.

$$\frac{17}{2}+\frac{9}{2}+\frac{81}{24}+\frac{271}{120}$$

Since \frac{17}{2} and \frac{9}{2} have the same denominator, add them by adding their numerators.

$$\frac{17+9}{2}+\frac{81}{24}+\frac{271}{120}$$

Add 17 and 9 to get 26.

$$\frac{26}{2}+\frac{81}{24}+\frac{271}{120}$$

Divide 26 by 2 to get 13.

$$13+\frac{81}{24}+\frac{271}{120}$$

Reduce the fraction \frac{81}{24} to lowest terms by extracting and canceling out 3.

$$13+\frac{27}{8}+\frac{271}{120}$$

Convert 13 to fraction \frac{104}{8}.

$$\frac{104}{8}+\frac{27}{8}+\frac{271}{120}$$

Since \frac{104}{8} and \frac{27}{8} have the same denominator, add them by adding their numerators.

$$\frac{104+27}{8}+\frac{271}{120}$$

Add 104 and 27 to get 131.

$$\frac{131}{8}+\frac{271}{120}$$

Least common multiple of 8 and 120 is 120. Convert \frac{131}{8} and \frac{271}{120} to fractions with denominator 120.

$$\frac{1965}{120}+\frac{271}{120}$$

Since \frac{1965}{120} and \frac{271}{120} have the same denominator, add them by adding their numerators.

$$\frac{1965+271}{120}$$

Add 1965 and 271 to get 2236.

$$\frac{2236}{120}$$

Reduce the fraction \frac{2236}{120} to lowest terms by extracting and canceling out 4.

$$\frac{559}{30}$$

Factor

$$\frac{13 \cdot 43}{2 \cdot 3 \cdot 5} = 18\frac{19}{30} = 18.633333333333333$$