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3\sqrt{2}-1+9\left(\sqrt{2}\right)^{2}-3\sqrt{2}
Apply the distributive property by multiplying each term of 1+3\sqrt{2} by each term of 3\sqrt{2}-1.
3\sqrt{2}-1+9\times 2-3\sqrt{2}
The square of \sqrt{2} is 2.
3\sqrt{2}-1+18-3\sqrt{2}
Multiply 9 and 2 to get 18.
3\sqrt{2}+17-3\sqrt{2}
Add -1 and 18 to get 17.
17
Combine 3\sqrt{2} and -3\sqrt{2} to get 0.