Solve (1+.5div2.05)=

$$(1+.5 \div 2.05)=$$

Evaluate

$$\frac{51}{41}\approx 1.243902439$$

Solution Steps

Expand \frac{0.5}{2.05} by multiplying both numerator and the denominator by 100.

$$1+\frac{50}{205}$$

Reduce the fraction \frac{50}{205} to lowest terms by extracting and canceling out 5.

$$1+\frac{10}{41}$$

Convert 1 to fraction \frac{41}{41}.

$$\frac{41}{41}+\frac{10}{41}$$

Since \frac{41}{41} and \frac{10}{41} have the same denominator, add them by adding their numerators.

$$\frac{41+10}{41}$$

Add 41 and 10 to get 51.

$$\frac{51}{41}$$

Factor

$$\frac{3 \cdot 17}{41} = 1\frac{10}{41} = 1.2439024390243902$$