Solve (1+(2*2)+3+4+5)div6

$$(1+(2 \times 2)+3+4+5) \div 6$$

Evaluate

$$\frac{17}{6}\approx 2.833333333$$

Solution Steps

Multiply 2 and 2 to get 4.

$$\frac{1+4+3+4+5}{6}$$

Add 1 and 4 to get 5.

$$\frac{5+3+4+5}{6}$$

Add 5 and 3 to get 8.

$$\frac{8+4+5}{6}$$

Add 8 and 4 to get 12.

$$\frac{12+5}{6}$$

Add 12 and 5 to get 17.

$$\frac{17}{6}$$

Factor

$$\frac{17}{2 \cdot 3} = 2\frac{5}{6} = 2.8333333333333335$$