Solve (1+2/5)x-20=(1-2/5)(300-x)

$$(1+ \frac{ 2 }{ 5 } )x-20=(1- \frac{ 2 }{ 5 } )(300-x)$$

Solve for x

$$x=100$$

Steps for Solving Linear Equation

Convert 1 to fraction \frac{5}{5}.

$$\left(\frac{5}{5}+\frac{2}{5}\right)x-20=\left(1-\frac{2}{5}\right)\left(300-x\right)$$

Since \frac{5}{5} and \frac{2}{5} have the same denominator, add them by adding their numerators.

$$\frac{5+2}{5}x-20=\left(1-\frac{2}{5}\right)\left(300-x\right)$$

Add 5 and 2 to get 7.

$$\frac{7}{5}x-20=\left(1-\frac{2}{5}\right)\left(300-x\right)$$

Convert 1 to fraction \frac{5}{5}.

$$\frac{7}{5}x-20=\left(\frac{5}{5}-\frac{2}{5}\right)\left(300-x\right)$$

Since \frac{5}{5} and \frac{2}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{7}{5}x-20=\frac{5-2}{5}\left(300-x\right)$$

Subtract 2 from 5 to get 3.

$$\frac{7}{5}x-20=\frac{3}{5}\left(300-x\right)$$

Use the distributive property to multiply \frac{3}{5} by 300-x.

$$\frac{7}{5}x-20=\frac{3}{5}\times 300+\frac{3}{5}\left(-1\right)x$$

Express \frac{3}{5}\times 300 as a single fraction.

$$\frac{7}{5}x-20=\frac{3\times 300}{5}+\frac{3}{5}\left(-1\right)x$$

Multiply 3 and 300 to get 900.

$$\frac{7}{5}x-20=\frac{900}{5}+\frac{3}{5}\left(-1\right)x$$

Divide 900 by 5 to get 180.

$$\frac{7}{5}x-20=180+\frac{3}{5}\left(-1\right)x$$

Multiply \frac{3}{5} and -1 to get -\frac{3}{5}.

$$\frac{7}{5}x-20=180-\frac{3}{5}x$$

Add \frac{3}{5}x to both sides.

$$\frac{7}{5}x-20+\frac{3}{5}x=180$$

Combine \frac{7}{5}x and \frac{3}{5}x to get 2x.

$$2x-20=180$$

Add 20 to both sides.

$$2x=180+20$$

Add 180 and 20 to get 200.

$$2x=200$$

Divide both sides by 2.

$$x=\frac{200}{2}$$

Divide 200 by 2 to get 100.

$$x=100$$