Solve (1div6)-(1div8)+(1div4)

$$(1 \div 6)-(1 \div 8)+(1 \div 4)$$

Evaluate

$$\frac{7}{24}\approx 0.291666667$$

Solution Steps

Least common multiple of 6 and 8 is 24. Convert \frac{1}{6} and \frac{1}{8} to fractions with denominator 24.

$$\frac{4}{24}-\frac{3}{24}+\frac{1}{4}$$

Since \frac{4}{24} and \frac{3}{24} have the same denominator, subtract them by subtracting their numerators.

$$\frac{4-3}{24}+\frac{1}{4}$$

Subtract 3 from 4 to get 1.

$$\frac{1}{24}+\frac{1}{4}$$

Least common multiple of 24 and 4 is 24. Convert \frac{1}{24} and \frac{1}{4} to fractions with denominator 24.

$$\frac{1}{24}+\frac{6}{24}$$

Since \frac{1}{24} and \frac{6}{24} have the same denominator, add them by adding their numerators.

$$\frac{1+6}{24}$$

Add 1 and 6 to get 7.

$$\frac{7}{24}$$

Factor

$$\frac{7}{2 ^ {3} \cdot 3} = 0.2916666666666667$$