Solve (0.4*10+2/5*2)-(2^2*0.2+0.2)=

$$(0.4 \times 10+ \frac{ 2 }{ 5 } \times 2)-( { 2 }^{ 2 } \times 0.2+0.2)=$$

Evaluate

$$3.8$$

Solution Steps

Multiply 0.4 and 10 to get 4.

$$4+\frac{2}{5}\times 2-\left(2^{2}\times 0.2+0.2\right)$$

Express \frac{2}{5}\times 2 as a single fraction.

$$4+\frac{2\times 2}{5}-\left(2^{2}\times 0.2+0.2\right)$$

Multiply 2 and 2 to get 4.

$$4+\frac{4}{5}-\left(2^{2}\times 0.2+0.2\right)$$

Convert 4 to fraction \frac{20}{5}.

$$\frac{20}{5}+\frac{4}{5}-\left(2^{2}\times 0.2+0.2\right)$$

Since \frac{20}{5} and \frac{4}{5} have the same denominator, add them by adding their numerators.

$$\frac{20+4}{5}-\left(2^{2}\times 0.2+0.2\right)$$

Add 20 and 4 to get 24.

$$\frac{24}{5}-\left(2^{2}\times 0.2+0.2\right)$$

Calculate 2 to the power of 2 and get 4.

$$\frac{24}{5}-\left(4\times 0.2+0.2\right)$$

Multiply 4 and 0.2 to get 0.8.

$$\frac{24}{5}-\left(0.8+0.2\right)$$

Add 0.8 and 0.2 to get 1.

$$\frac{24}{5}-1$$

Convert 1 to fraction \frac{5}{5}.

$$\frac{24}{5}-\frac{5}{5}$$

Since \frac{24}{5} and \frac{5}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{24-5}{5}$$

Subtract 5 from 24 to get 19.

$$\frac{19}{5}$$

Factor

$$\frac{19}{5} = 3\frac{4}{5} = 3.8$$