Solve (-8-1)*(3-(-72)div(-25+3)

$$(-8-1) \times (3-(-72) \div (-25+3)$$

Evaluate

$$\frac{27}{11}\approx 2.454545455$$

Solution Steps

Subtract 1 from -8 to get -9.

$$-9\left(3-\frac{-72}{-25+3}\right)$$

Add -25 and 3 to get -22.

$$-9\left(3-\frac{-72}{-22}\right)$$

Reduce the fraction \frac{-72}{-22} to lowest terms by extracting and canceling out -2.

$$-9\left(3-\frac{36}{11}\right)$$

Convert 3 to fraction \frac{33}{11}.

$$-9\left(\frac{33}{11}-\frac{36}{11}\right)$$

Since \frac{33}{11} and \frac{36}{11} have the same denominator, subtract them by subtracting their numerators.

$$-9\times \frac{33-36}{11}$$

Subtract 36 from 33 to get -3.

$$-9\left(-\frac{3}{11}\right)$$

Express -9\left(-\frac{3}{11}\right) as a single fraction.

$$\frac{-9\left(-3\right)}{11}$$

Multiply -9 and -3 to get 27.

$$\frac{27}{11}$$

Factor

$$\frac{3 ^ {3}}{11} = 2\frac{5}{11} = 2.4545454545454546$$