Solve (-6+6)*(41+-2)sqrt{599^2*100}

$$(-6+6) \times (41+-2) \sqrt{ { 599 }^{ 2 } \times 100 }$$

Evaluate

$$0$$

Solution Steps

Add -6 and 6 to get 0.

$$0\left(41-2\right)\sqrt{599^{2}\times 100}$$

Subtract 2 from 41 to get 39.

$$0\times 39\sqrt{599^{2}\times 100}$$

Multiply 0 and 39 to get 0.

$$0\sqrt{599^{2}\times 100}$$

Calculate 599 to the power of 2 and get 358801.

$$0\sqrt{358801\times 100}$$

Multiply 358801 and 100 to get 35880100.

$$0\sqrt{35880100}$$

Calculate the square root of 35880100 and get 5990.

$$0\times 5990$$

Multiply 0 and 5990 to get 0.

$$0$$

Factor

$$0$$