Solve (-5+2^2)div(-9)-lfloor2-(-4-2)-(-1^3)*(-5+8)rfloor

$$(-5+ { 2 }^{ 2 } ) \div (-9)- \lfloor 2-(-4-2)-(- { 1 }^{ 3 } ) \times (-5+8) \rfloor$$

Evaluate

$$-\frac{98}{9}\approx -10.888888889$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$\frac{-5+4}{-9}-\lfloor 2-\left(-4-2\right)-\left(-1^{3}\right)\left(-5+8\right)\rfloor$$

Add -5 and 4 to get -1.

$$\frac{-1}{-9}-\lfloor 2-\left(-4-2\right)-\left(-1^{3}\right)\left(-5+8\right)\rfloor$$

Fraction \frac{-1}{-9} can be simplified to \frac{1}{9} by removing the negative sign from both the numerator and the denominator.

$$\frac{1}{9}-\lfloor 2-\left(-4-2\right)-\left(-1^{3}\right)\left(-5+8\right)\rfloor$$

Subtract 2 from -4 to get -6.

$$\frac{1}{9}-\lfloor 2-\left(-6\right)-\left(-1^{3}\right)\left(-5+8\right)\rfloor$$

The opposite of -6 is 6.

$$\frac{1}{9}-\lfloor 2+6-\left(-1^{3}\right)\left(-5+8\right)\rfloor$$

Add 2 and 6 to get 8.

$$\frac{1}{9}-\lfloor 8-\left(-1^{3}\right)\left(-5+8\right)\rfloor$$

Calculate 1 to the power of 3 and get 1.

$$\frac{1}{9}-\lfloor 8-\left(-\left(-5+8\right)\right)\rfloor$$

Add -5 and 8 to get 3.

$$\frac{1}{9}-\lfloor 8-\left(-3\right)\rfloor$$

The opposite of -3 is 3.

$$\frac{1}{9}-\lfloor 8+3\rfloor$$

Add 8 and 3 to get 11.

$$\frac{1}{9}-\lfloor 11\rfloor$$

The floor of a real number a is the largest integer number less than or equal to a. The floor of 11 is 11.

$$\frac{1}{9}-11$$

Convert 11 to fraction \frac{99}{9}.

$$\frac{1}{9}-\frac{99}{9}$$

Since \frac{1}{9} and \frac{99}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1-99}{9}$$

Subtract 99 from 1 to get -98.

$$-\frac{98}{9}$$

Factor

$$-\frac{98}{9} = -10\frac{8}{9} = -10.88888888888889$$