Solve (-20-25.1x1+40.5x2=0

$$(-20-25.1x1+40.5x2 = 0$$

Solve for x_1

$$x_{1}=\frac{405x_{2}-200}{251}$$

Steps for Solving Linear Equation

Add 20 to both sides. Anything plus zero gives itself.

$$-25.1x_{1}+40.5x_{2}=20$$

Subtract 40.5x_{2} from both sides.

$$-25.1x_{1}=20-40.5x_{2}$$

The equation is in standard form.

$$-25.1x_{1}=-\frac{81x_{2}}{2}+20$$

Divide both sides of the equation by -25.1, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-25.1x_{1}}{-25.1}=\frac{-\frac{81x_{2}}{2}+20}{-25.1}$$

Dividing by -25.1 undoes the multiplication by -25.1.

$$x_{1}=\frac{-\frac{81x_{2}}{2}+20}{-25.1}$$

Divide 20-\frac{81x_{2}}{2} by -25.1 by multiplying 20-\frac{81x_{2}}{2} by the reciprocal of -25.1.

$$x_{1}=\frac{405x_{2}-200}{251}$$

Solve for x_2

$$x_{2}=\frac{251x_{1}}{405}+\frac{40}{81}$$

Steps for Solving Linear Equation

Add 20 to both sides. Anything plus zero gives itself.

$$-25.1x_{1}+40.5x_{2}=20$$

Add 25.1x_{1} to both sides.

$$40.5x_{2}=20+25.1x_{1}$$

The equation is in standard form.

$$40.5x_{2}=\frac{251x_{1}}{10}+20$$

Divide both sides of the equation by 40.5, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{40.5x_{2}}{40.5}=\frac{\frac{251x_{1}}{10}+20}{40.5}$$

Dividing by 40.5 undoes the multiplication by 40.5.

$$x_{2}=\frac{\frac{251x_{1}}{10}+20}{40.5}$$

Divide 20+\frac{251x_{1}}{10} by 40.5 by multiplying 20+\frac{251x_{1}}{10} by the reciprocal of 40.5.

$$x_{2}=\frac{251x_{1}}{405}+\frac{40}{81}$$