Solve (-2+3*(2-5)div3)-((3-5+2)-2-(3-4))

$$(-2+3 \times (2-5) \div 3)-((3-5+2)-2-(3-4))$$

Evaluate

$$-4$$

Solution Steps

Cancel out 3 and 3.

$$-2+2-5-\left(3-5+2-2-\left(3-4\right)\right)$$

Subtract 5 from 2 to get -3.

$$-2-3-\left(3-5+2-2-\left(3-4\right)\right)$$

Subtract 3 from -2 to get -5.

$$-5-\left(3-5+2-2-\left(3-4\right)\right)$$

Subtract 5 from 3 to get -2.

$$-5-\left(-2+2-2-\left(3-4\right)\right)$$

Add -2 and 2 to get 0.

$$-5-\left(-2-\left(3-4\right)\right)$$

Subtract 4 from 3 to get -1.

$$-5-\left(-2-\left(-1\right)\right)$$

The opposite of -1 is 1.

$$-5-\left(-2+1\right)$$

Add -2 and 1 to get -1.

$$-5-\left(-1\right)$$

The opposite of -1 is 1.

$$-5+1$$

Add -5 and 1 to get -4.

$$-4$$

Factor

$$-4$$