Solve (-06x-7/2y)-(-7/5x-25z)+(+12x-16y)

$$(-06x- \frac{ 7 }{ 2 } y)-(- \frac{ 7 }{ 5 } x-25z)+(+12x-16y)$$

Evaluate

$$\frac{67x}{5}-\frac{39y}{2}+25z$$

Solution Steps

Multiply 0 and 6 to get 0.

$$0x-\frac{7}{2}y-\left(-\frac{7}{5}x-25z\right)+12x-16y$$

Anything times zero gives zero.

$$0-\frac{7}{2}y-\left(-\frac{7}{5}x-25z\right)+12x-16y$$

To find the opposite of -\frac{7}{5}x-25z, find the opposite of each term.

$$0-\frac{7}{2}y-\left(-\frac{7}{5}x\right)-\left(-25z\right)+12x-16y$$

The opposite of -\frac{7}{5}x is \frac{7}{5}x.

$$0-\frac{7}{2}y+\frac{7}{5}x-\left(-25z\right)+12x-16y$$

The opposite of -25z is 25z.

$$0-\frac{7}{2}y+\frac{7}{5}x+25z+12x-16y$$

Combine \frac{7}{5}x and 12x to get \frac{67}{5}x.

$$0-\frac{7}{2}y+\frac{67}{5}x+25z-16y$$

Combine -\frac{7}{2}y and -16y to get -\frac{39}{2}y.

$$0-\frac{39}{2}y+\frac{67}{5}x+25z$$

Anything plus zero gives itself.

$$-\frac{39}{2}y+\frac{67}{5}x+25z$$

Expand

$$\frac{67x}{5}-\frac{39y}{2}+25z$$

Solution Steps

Multiply 0 and 6 to get 0.

$$0x-\frac{7}{2}y-\left(-\frac{7}{5}x-25z\right)+12x-16y$$

Anything times zero gives zero.

$$0-\frac{7}{2}y-\left(-\frac{7}{5}x-25z\right)+12x-16y$$

To find the opposite of -\frac{7}{5}x-25z, find the opposite of each term.

$$0-\frac{7}{2}y-\left(-\frac{7}{5}x\right)-\left(-25z\right)+12x-16y$$

The opposite of -\frac{7}{5}x is \frac{7}{5}x.

$$0-\frac{7}{2}y+\frac{7}{5}x-\left(-25z\right)+12x-16y$$

The opposite of -25z is 25z.

$$0-\frac{7}{2}y+\frac{7}{5}x+25z+12x-16y$$

Combine \frac{7}{5}x and 12x to get \frac{67}{5}x.

$$0-\frac{7}{2}y+\frac{67}{5}x+25z-16y$$

Combine -\frac{7}{2}y and -16y to get -\frac{39}{2}y.

$$0-\frac{39}{2}y+\frac{67}{5}x+25z$$

Anything plus zero gives itself.

$$-\frac{39}{2}y+\frac{67}{5}x+25z$$