Solve (-0.12)*(3/4-1/6+1)

$$(-0.12) \times ( \frac{ 3 }{ 4 } - \frac{ 1 }{ 6 } +1)$$

Evaluate

$$-0.19$$

Solution Steps

Least common multiple of 4 and 6 is 12. Convert \frac{3}{4} and \frac{1}{6} to fractions with denominator 12.

$$-0.12\left(\frac{9}{12}-\frac{2}{12}+1\right)$$

Since \frac{9}{12} and \frac{2}{12} have the same denominator, subtract them by subtracting their numerators.

$$-0.12\left(\frac{9-2}{12}+1\right)$$

Subtract 2 from 9 to get 7.

$$-0.12\left(\frac{7}{12}+1\right)$$

Convert 1 to fraction \frac{12}{12}.

$$-0.12\left(\frac{7}{12}+\frac{12}{12}\right)$$

Since \frac{7}{12} and \frac{12}{12} have the same denominator, add them by adding their numerators.

$$-0.12\times \frac{7+12}{12}$$

Add 7 and 12 to get 19.

$$-0.12\times \frac{19}{12}$$

Convert decimal number -0.12 to fraction -\frac{12}{100}. Reduce the fraction -\frac{12}{100} to lowest terms by extracting and canceling out 4.

$$-\frac{3}{25}\times \frac{19}{12}$$

Multiply -\frac{3}{25} times \frac{19}{12} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-3\times 19}{25\times 12}$$

Do the multiplications in the fraction \frac{-3\times 19}{25\times 12}.

$$\frac{-57}{300}$$

Reduce the fraction \frac{-57}{300} to lowest terms by extracting and canceling out 3.

$$-\frac{19}{100}$$

Factor

$$-0.19$$