Solve (-16/3+(4+4)

$$(- \frac{ 16 }{ 3 } +(4+4)$$

Evaluate

$$\frac{8}{3}\approx 2.666666667$$

Solution Steps

Convert 4 to fraction \frac{12}{3}.

$$-\frac{16}{3}+\frac{12}{3}+4$$

Since -\frac{16}{3} and \frac{12}{3} have the same denominator, add them by adding their numerators.

$$\frac{-16+12}{3}+4$$

Add -16 and 12 to get -4.

$$-\frac{4}{3}+4$$

Convert 4 to fraction \frac{12}{3}.

$$-\frac{4}{3}+\frac{12}{3}$$

Since -\frac{4}{3} and \frac{12}{3} have the same denominator, add them by adding their numerators.

$$\frac{-4+12}{3}$$

Add -4 and 12 to get 8.

$$\frac{8}{3}$$

Factor

$$\frac{2 ^ {3}}{3} = 2\frac{2}{3} = 2.6666666666666665$$