Solve (-1/2-08+3/5)*(3+5/8+5

$$(- \frac{ 1 }{ 2 } -08+ \frac{ 3 }{ 5 } ) \times (3+ \frac{ 5 }{ 8+5 }$$

Evaluate

$$-\frac{1738}{65}\approx -26.738461538$$

Solution Steps

Convert 8 to fraction \frac{16}{2}.

$$\left(-\frac{1}{2}-\frac{16}{2}+\frac{3}{5}\right)\left(3+\frac{5}{8+5}\right)$$

Since -\frac{1}{2} and \frac{16}{2} have the same denominator, subtract them by subtracting their numerators.

$$\left(\frac{-1-16}{2}+\frac{3}{5}\right)\left(3+\frac{5}{8+5}\right)$$

Subtract 16 from -1 to get -17.

$$\left(-\frac{17}{2}+\frac{3}{5}\right)\left(3+\frac{5}{8+5}\right)$$

Least common multiple of 2 and 5 is 10. Convert -\frac{17}{2} and \frac{3}{5} to fractions with denominator 10.

$$\left(-\frac{85}{10}+\frac{6}{10}\right)\left(3+\frac{5}{8+5}\right)$$

Since -\frac{85}{10} and \frac{6}{10} have the same denominator, add them by adding their numerators.

$$\frac{-85+6}{10}\left(3+\frac{5}{8+5}\right)$$

Add -85 and 6 to get -79.

$$-\frac{79}{10}\left(3+\frac{5}{8+5}\right)$$

Add 8 and 5 to get 13.

$$-\frac{79}{10}\left(3+\frac{5}{13}\right)$$

Convert 3 to fraction \frac{39}{13}.

$$-\frac{79}{10}\left(\frac{39}{13}+\frac{5}{13}\right)$$

Since \frac{39}{13} and \frac{5}{13} have the same denominator, add them by adding their numerators.

$$-\frac{79}{10}\times \frac{39+5}{13}$$

Add 39 and 5 to get 44.

$$-\frac{79}{10}\times \frac{44}{13}$$

Multiply -\frac{79}{10} times \frac{44}{13} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-79\times 44}{10\times 13}$$

Do the multiplications in the fraction \frac{-79\times 44}{10\times 13}.

$$\frac{-3476}{130}$$

Reduce the fraction \frac{-3476}{130} to lowest terms by extracting and canceling out 2.

$$-\frac{1738}{65}$$

Factor

$$-\frac{1738}{65} = -26\frac{48}{65} = -26.73846153846154$$