Solve ((x+x+3.6+3.6+3.8+4+4.5)*3+4-3.6+1.9*13.5)div(21+13.5)=3

$$((x+x+3.6+3.6+3.8+4+4.5) \times 3+4-3.6+1.9 \times 13.5) \div (21+13.5)=3$$

Solve for x

$$x = \frac{379}{120} = 3\frac{19}{120} \approx 3.158333333$$

Steps for Solving Linear Equation

Combine x and x to get 2x.

$$\frac{\left(2x+3.6+3.6+3.8+4+4.5\right)\times 3+4-3.6+1.9\times 13.5}{21+13.5}=3$$

Add 3.6 and 3.6 to get 7.2.

$$\frac{\left(2x+7.2+3.8+4+4.5\right)\times 3+4-3.6+1.9\times 13.5}{21+13.5}=3$$

Add 7.2 and 3.8 to get 11.

$$\frac{\left(2x+11+4+4.5\right)\times 3+4-3.6+1.9\times 13.5}{21+13.5}=3$$

Add 11 and 4 to get 15.

$$\frac{\left(2x+15+4.5\right)\times 3+4-3.6+1.9\times 13.5}{21+13.5}=3$$

Add 15 and 4.5 to get 19.5.

$$\frac{\left(2x+19.5\right)\times 3+4-3.6+1.9\times 13.5}{21+13.5}=3$$

Subtract 3.6 from 4 to get 0.4.

$$\frac{\left(2x+19.5\right)\times 3+0.4+1.9\times 13.5}{21+13.5}=3$$

Multiply 1.9 and 13.5 to get 25.65.

$$\frac{\left(2x+19.5\right)\times 3+0.4+25.65}{21+13.5}=3$$

Add 0.4 and 25.65 to get 26.05.

$$\frac{\left(2x+19.5\right)\times 3+26.05}{21+13.5}=3$$

Add 21 and 13.5 to get 34.5.

$$\frac{\left(2x+19.5\right)\times 3+26.05}{34.5}=3$$

Use the distributive property to multiply 2x+19.5 by 3.

$$\frac{6x+58.5+26.05}{34.5}=3$$

Add 58.5 and 26.05 to get 84.55.

$$\frac{6x+84.55}{34.5}=3$$

Divide each term of 6x+84.55 by 34.5 to get \frac{6x}{34.5}+\frac{84.55}{34.5}.

$$\frac{6x}{34.5}+\frac{84.55}{34.5}=3$$

Divide 6x by 34.5 to get \frac{4}{23}x.

$$\frac{4}{23}x+\frac{84.55}{34.5}=3$$

Expand \frac{84.55}{34.5} by multiplying both numerator and the denominator by 100.

$$\frac{4}{23}x+\frac{8455}{3450}=3$$

Reduce the fraction \frac{8455}{3450} to lowest terms by extracting and canceling out 5.

$$\frac{4}{23}x+\frac{1691}{690}=3$$

Subtract \frac{1691}{690} from both sides.

$$\frac{4}{23}x=3-\frac{1691}{690}$$

Convert 3 to fraction \frac{2070}{690}.

$$\frac{4}{23}x=\frac{2070}{690}-\frac{1691}{690}$$

Since \frac{2070}{690} and \frac{1691}{690} have the same denominator, subtract them by subtracting their numerators.

$$\frac{4}{23}x=\frac{2070-1691}{690}$$

Subtract 1691 from 2070 to get 379.

$$\frac{4}{23}x=\frac{379}{690}$$

Divide both sides by \frac{4}{23}.

$$x=\frac{\frac{379}{690}}{\frac{4}{23}}$$

Express \frac{\frac{379}{690}}{\frac{4}{23}} as a single fraction.

$$x=\frac{379}{690\times \frac{4}{23}}$$

Multiply 690 and \frac{4}{23} to get 120.

$$x=\frac{379}{120}$$