Solve ((54.80+3*63.40)div24)+5.45

$$((54.80+3 \times 63.40) \div 24)+5.45$$

Evaluate

$$\frac{1879}{120}\approx 15.658333333$$

Solution Steps

Multiply 3 and 63.4 to get 190.2.

$$\frac{54.8+190.2}{24}+5.45$$

Add 54.8 and 190.2 to get 245.

$$\frac{245}{24}+5.45$$

Convert decimal number 5.45 to fraction \frac{545}{100}. Reduce the fraction \frac{545}{100} to lowest terms by extracting and canceling out 5.

$$\frac{245}{24}+\frac{109}{20}$$

Least common multiple of 24 and 20 is 120. Convert \frac{245}{24} and \frac{109}{20} to fractions with denominator 120.

$$\frac{1225}{120}+\frac{654}{120}$$

Since \frac{1225}{120} and \frac{654}{120} have the same denominator, add them by adding their numerators.

$$\frac{1225+654}{120}$$

Add 1225 and 654 to get 1879.

$$\frac{1879}{120}$$

Factor

$$\frac{1879}{3 \cdot 5 \cdot 2 ^ {3}} = 15\frac{79}{120} = 15.658333333333333$$