Solve ((5+36+36+38+4+45)*3+45-36+36+19*135)div(22+135=

$$((5+36+36+38+4+45) \times 3+45-36+36+19 \times 135) \div (22+135=$$

Evaluate

$$\frac{3102}{157}\approx 19.757961783$$

Solution Steps

Add 5 and 36 to get 41.

$$\frac{\left(41+36+38+4+45\right)\times 3+45-36+36+19\times 135}{22+135}$$

Add 41 and 36 to get 77.

$$\frac{\left(77+38+4+45\right)\times 3+45-36+36+19\times 135}{22+135}$$

Add 77 and 38 to get 115.

$$\frac{\left(115+4+45\right)\times 3+45-36+36+19\times 135}{22+135}$$

Add 115 and 4 to get 119.

$$\frac{\left(119+45\right)\times 3+45-36+36+19\times 135}{22+135}$$

Add 119 and 45 to get 164.

$$\frac{164\times 3+45-36+36+19\times 135}{22+135}$$

Multiply 164 and 3 to get 492.

$$\frac{492+45-36+36+19\times 135}{22+135}$$

Add 492 and 45 to get 537.

$$\frac{537-36+36+19\times 135}{22+135}$$

Subtract 36 from 537 to get 501.

$$\frac{501+36+19\times 135}{22+135}$$

Add 501 and 36 to get 537.

$$\frac{537+19\times 135}{22+135}$$

Multiply 19 and 135 to get 2565.

$$\frac{537+2565}{22+135}$$

Add 537 and 2565 to get 3102.

$$\frac{3102}{22+135}$$

Add 22 and 135 to get 157.

$$\frac{3102}{157}$$

Factor

$$\frac{2 \cdot 3 \cdot 11 \cdot 47}{157} = 19\frac{119}{157} = 19.75796178343949$$