Solve ((2+7/15)-4)*((8+16/23)-10)

$$((2+ \frac{ 7 }{ 15 } )-4) \times ((8+ \frac{ 16 }{ 23 } )-10)$$

Evaluate

$$2$$

Solution Steps

Convert 2 to fraction \frac{30}{15}.

$$\left(\frac{30}{15}+\frac{7}{15}-4\right)\left(8+\frac{16}{23}-10\right)$$

Since \frac{30}{15} and \frac{7}{15} have the same denominator, add them by adding their numerators.

$$\left(\frac{30+7}{15}-4\right)\left(8+\frac{16}{23}-10\right)$$

Add 30 and 7 to get 37.

$$\left(\frac{37}{15}-4\right)\left(8+\frac{16}{23}-10\right)$$

Convert 4 to fraction \frac{60}{15}.

$$\left(\frac{37}{15}-\frac{60}{15}\right)\left(8+\frac{16}{23}-10\right)$$

Since \frac{37}{15} and \frac{60}{15} have the same denominator, subtract them by subtracting their numerators.

$$\frac{37-60}{15}\left(8+\frac{16}{23}-10\right)$$

Subtract 60 from 37 to get -23.

$$-\frac{23}{15}\left(8+\frac{16}{23}-10\right)$$

Convert 8 to fraction \frac{184}{23}.

$$-\frac{23}{15}\left(\frac{184}{23}+\frac{16}{23}-10\right)$$

Since \frac{184}{23} and \frac{16}{23} have the same denominator, add them by adding their numerators.

$$-\frac{23}{15}\left(\frac{184+16}{23}-10\right)$$

Add 184 and 16 to get 200.

$$-\frac{23}{15}\left(\frac{200}{23}-10\right)$$

Convert 10 to fraction \frac{230}{23}.

$$-\frac{23}{15}\left(\frac{200}{23}-\frac{230}{23}\right)$$

Since \frac{200}{23} and \frac{230}{23} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{23}{15}\times \frac{200-230}{23}$$

Subtract 230 from 200 to get -30.

$$-\frac{23}{15}\left(-\frac{30}{23}\right)$$

Multiply -\frac{23}{15} times -\frac{30}{23} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-23\left(-30\right)}{15\times 23}$$

Do the multiplications in the fraction \frac{-23\left(-30\right)}{15\times 23}.

$$\frac{690}{345}$$

Divide 690 by 345 to get 2.

$$2$$

Factor

$$2$$