Solve ((-3)*(9-5)-(6-10))div(-2)-left|10-16right|

$$((-3) \times (9-5)-(6-10)) \div (-2)- \left| 10-16 \right|$$

Evaluate

$$-2$$

Solution Steps

Subtract 5 from 9 to get 4.

$$\frac{-3\times 4-\left(6-10\right)}{-2}-|10-16|$$

Multiply -3 and 4 to get -12.

$$\frac{-12-\left(6-10\right)}{-2}-|10-16|$$

Subtract 10 from 6 to get -4.

$$\frac{-12-\left(-4\right)}{-2}-|10-16|$$

The opposite of -4 is 4.

$$\frac{-12+4}{-2}-|10-16|$$

Add -12 and 4 to get -8.

$$\frac{-8}{-2}-|10-16|$$

Divide -8 by -2 to get 4.

$$4-|10-16|$$

Subtract 16 from 10 to get -6.

$$4-|-6|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -6 is 6.

$$4-6$$

Subtract 6 from 4 to get -2.

$$-2$$

Factor

$$-2$$